Answer to Question #240513 in General Chemistry for Pyxile

Question

A metal radiator is made from 26.0 kg of iron. The specific heat of iron is 0.449 How much heat must be supplied to the radiator to raise its temperature from 25.0 to 55.0

Answer 1

The formula for calculating heat energy is

Q = mc ΔT

Solution :

= (26.0 x 10^3 g)(0.449 J/g°C)(55°C - 25°C)

= 350220 J or

= 350.22 kJ