Question #240513
A metal radiator is made from 26.0 kg of iron. The specific heat of iron is 0.449 How much heat must be supplied to the radiator to raise its temperature from 25.0 to 55.0
1
Expert's answer
2021-09-23T02:37:52-0400

The formula for calculating heat energy is


Q = mc ΔT


Solution :


= (26.0 x 10^3 g)(0.449 J/g°C)(55°C - 25°C)


= 350220 J or


= 350.22 kJ




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