Answer to Question #240387 in General Chemistry for RunicFlame

Question

How many moles of PCl5 can be produced from 50.0 g of Cl2 (and excess P4)?

Answer 1

The balanced chemical equation is

P₄ + 10Cl₂ = 4PCl_5[sub]

_{The mass of chlorine is m(Cl[sub]2}) = 59.0 g

The amount of chlorine is n(Cl₂) = m(Cl₂)$/$ M(Cl₂) = 59$/$ 70.906 = 0.832 mol

10 moles of Cl₂ yield 4 moles of PCl₅;

0.832 of Cl₂ yield $\times$ moles of PCl₅

n(PCl₅) = 4$\times$ 0.832$/$ 10 = 0.333 mol

Answer: 0.333 mol