One Ethane ( "C_2H_6" ) molecule has 6 H atoms
1 Mole of "C_2H_6" = Gram Molecular Weight of "C_2H_6"
= (2 x 12) + (6 x 1)
= 30 g
mass of "C_2H_6=30\\times4.2=126g"
We know that 1 Mole of "C_2H_6" has Avogadro number of Molecules
Avogadro number = 6.023 x1023
But here he is asking about number of H atoms. So,
1 Mole "C_2H_6" has (6 x 6.023 x1023 ) H atoms
30 g of C2H6 has ( 6 x 6.023 x 1023 ) H atoms
126 g of C2H6 has ? H atoms
= 126 g x (6 x 6.023 x 1023) H atoms "\/" 30 g="1.52\\times 10^{25} atoms"
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