Answer to Question #240348 in General Chemistry for Nia

General Chemistry

Question #240348

A balloon has a volume of 6.25 L at 453 kPa. What would the volume of this balloon be at 325 kPa

Expert's answer

Answer:

4.48 L

Explanation:

P1/V1 = P2/V2

453/6.25 = 325/ x

453x = 6.25*325

x = (6.25*325)/453

x = 4.48 L

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