Answer to Question #239912 in General Chemistry for Ntokozo

Question

In the titration of 25 ml of 0,05M of AgNO3 solution with 0,02M KSCN solution, Ag in the conical flak solution after the following additions of titrant KSCN solution;(1) 39 ml (2) at equivalence point (3) 100 ml. Ksp (AgSCN)

Answer 1

Moles of $AgNO_3=0.05×\frac{25}{1000}=0.00625moles$

AgNO₃ + KSCN → KNO₃ + AgSCN

Mole ratio 1:1

Volume of KSCN$=\frac{0.00625×100}{0.02}=312.5ml$