Question

In the titration of 25 ml of 0,05M of AgNO3 solution with 0,02M KSCN solution, Ag in the conical flak solution after the following additions of titrant KSCN solution;(1) 39 ml (2) at equivalence point (3) 100 ml. Ksp (AgSCN)

Answer 1

Moles of $AgNO_3=0.05×\frac{25}{1000}=0.00625moles$

AgNO₃ + KSCN → KNO₃ + AgSCN

Mole ratio 1:1

Volume of KSCN$=\frac{0.00625×100}{0.02}=312.5ml$