what volume of 0.98 m phosphoric acid is required to completely neutralize 18.0ml of 2.15 solution of potassium hydroxide
3KOH + H3PO4 → K3PO4 + 3H2O
Moles of KOH "=2.15\u00d7\\frac{18.0}{1000}=0.0387moles"
Moles of H3PO4 "=\\frac{0.0387}{3}=0.0129moles"
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