Question

what volume of 0.98 m phosphoric acid is required to completely neutralize 18.0ml of 2.15 solution of potassium hydroxide

Answer 1

3KOH + H₃PO₄ → K₃PO₄ + 3H₂O

Moles of KOH $=2.15×\frac{18.0}{1000}=0.0387moles$

Moles of H₃PO₄ $=\frac{0.0387}{3}=0.0129moles$