Question

What mass of C₆H₁₂O₆ (glucose) is needed to prepare 600.0 mL of a 0.789 M solution of glucose in water?

Answer 1

Moles of C₆H₁₂O₆$=0.789×\frac{600}{1000}=0.4734moles$

Mass =$180.156 ×0.4734=85.29grams$