Calculate the standard enthalpy change for the reaction 2𝐴𝑙(𝑠) + 𝐹𝑒2𝑂3(𝑠) → 2𝐹𝑒(𝑠) + 𝐴𝑙2𝑂3(𝑠)
given that
2𝐴𝑙(𝑠)+3𝑂 (𝑔)→𝐴𝑙 𝑂 (𝑠) ∆𝐻° =−1669.8 𝑘𝐽 22 23 𝑟𝑥𝑛 𝑚𝑜𝑙
2𝐹𝑒(𝑠)+3𝑂 (𝑔)→𝐹𝑒 𝑂 (𝑠) ∆𝐻° =−822.2 𝑘𝐽 22 23 𝑟𝑥𝑛 𝑚𝑜𝑙
Enthalpy change=1669.8+822.2=−847.6=1669.8+822.2=-847.6=1669.8+822.2=−847.6 22 23 𝑟𝑥𝑛 𝑚𝑜𝑙
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