Answer to Question #239129 in General Chemistry for KING

Question

A sheet of gold weighing 10.0 g and at a temperature of 18.0°C is placed flat on a sheet of iron weighing 20.0 g and at a temperature of 55.6°C. What is the final temperature of the combined metals? Assume that no heat is lost to the surroundings. (Hint: The heat gained by the gold must be equal to the heat lost by the iron. The

specific heats of the gold and iron are 0.129 and 0.444 𝐽 , respectively

Answer 1

Let the final temperature be T .

heat lost = mass x specific heat x fall in temperature

heat lost by iron = 20 x .444 x ( 55.6 - T )

heat gained by gold = 10 x .129 x ( T- 18 )

heat lost = heat gained

20 x .444 x ( 55.6 - T ) = 10 x .129 x ( T- 18 )

493.73 - 8.88 T = 1.29 T - 23.22

10.17 T = 516.95

T = 50.83°C