Answer to Question #239126 in General Chemistry for KING

Question #239126

The first step in the industrial recovery of zinc from the zinc sulfide ore is roasting, that is, the conversion of ZnS to ZnO by heating:

2𝑍𝑛𝑆(𝑠) + 3𝑂2(𝑔) β†’ 2𝑍𝑛𝑂(𝑠) + 2𝑆𝑂2(𝑔) βˆ†π» = βˆ’879 π‘˜π½ π‘šπ‘œπ‘™

Calculate the heat evolved (in kJ) per gram of ZnS roasted


1
Expert's answer
2021-09-21T01:54:17-0400

In this item, we are provided the heat released for each 2mols of ZnS is 879kJ

Amount of ZnS = 2mols of ZnS Γ—97.474g/mol = 194.9 g ZnS

Heat released = 879/194.9

= 4.5kJ/g


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