A sample of nitrogen gas expands in volume from 1.6 L to 5.4 L at constant temperature. Calculate the work done in joules if the gas expands against a constant pressure of 0.80 atm
Work done , W = PdV
= P ×( Vf - Vi )
Where
P = external pressure = 0.80 atm = 0.80× 101.3×10^3 Pa( Since 1 atm = 101.3×10^3 Pa)
= 81040 Pa
Vf = final volume = 5.4 L
Vi = initial volume = 1.6 L
So dV = 5.4-1.6 = 3.8 L = 3.8×10^-3 m^3
So Work done ,W = 81040× 3.8×10^-3 J
= 307.9 J
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