In June 2024
Answer to Question #238787 in General Chemistry for Ins
an excess of copper(II) oxide is reacted with 1.0 mol dm3 sulphuric acid. Calculate the volume of sulphuric acid needed to prepare 20.0 g of copper(II) sulphate.
CuO + H2SO4 ==> CuSO4 + H2O.....
moles of H2SO4 = moles of CuSO4= (20/159.6) = 0.12531....
Volume of acid= ( 0.12531 × 1000)/1.0
= 125.3 mL
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