We have 11.2 l O2 available, how many grams of oxygen correspond to this volume under standard conditions? Ar(O) = 16
one mole of oxygen correspond to 22.4l at STP
what about 11.2l?
number of moles of "O_2=11.2\/22.4=0.5"
mass of oxygen "=0.5(16\\times 2)=16g"
Comments
Leave a comment