We have 11.2 l O2 available, how many grams of oxygen correspond to this volume under standard conditions? Ar(O) = 16
one mole of oxygen correspond to 22.4l at STP
what about 11.2l?
number of moles of O2=11.2/22.4=0.5O_2=11.2/22.4=0.5O2=11.2/22.4=0.5
mass of oxygen =0.5(16×2)=16g=0.5(16\times 2)=16g=0.5(16×2)=16g
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