Answer to Question #238541 in General Chemistry for KING

Question

 A sample of nitrogen gas expands in volume from 1.6 L to 5.4 L at constant temperature. Calculate the work done in joules if the gas expands (a) against a vacuum, (b) against a constant pressure of 0.80 atm, and (c) against a constant pressure of 3.7 atm.

Answer 1

Solution

a.) $W = -0 ×(5.4-1.6) L = 0$ J

b.) $P = 0.80$

$V2-V1 = ( 5.4-1.6) = 3.8 L$

$1 L.atm = 101.325 J$

$W= - 0.80×3.8 = -3.04$

$= -3.04×101.325 J = -308.03 J$

c.)$P = 3.7 atm$

$V2-V1 = ( 5.4-1.6) = 3.8 L$

$W = - 3.7×3.8 = -14.06 L.atm$

=$-14.06×101.325 J$

$= -1424.63 J$