Question

if 45.90 mol of glucose is present in the oxidation, how many moles of CO2 are produced?

Answer 1

Write a balanced chemical equation

$C_2H_{12}O_6+6O_2\to 6CO_2+6H_2O$

Mole ratio; $C_6H_{12}O_6:6CO_2=1:6$

Moles of $CO_2$ produced $=45.90\times 6=275.4$