if 45.90 mol of glucose is present in the oxidation, how many moles of CO2 are produced?
Write a balanced chemical equation
"C_2H_{12}O_6+6O_2\\to 6CO_2+6H_2O"
Mole ratio; "C_6H_{12}O_6:6CO_2=1:6"
Moles of "CO_2" produced "=45.90\\times 6=275.4"
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