Answer to Question #238365 in General Chemistry for rose

Question

How many milliliters of 9.26 M nitric acid solution should be used to prepare 5.00 L of 0.600 M ?

Answer 1

C₁*V₁=C₂*V₂

C₁=9.6 M

V₂=5.00 L

C₂=0.6 M

V₁ -?

V₁=C₂*V₂/C₁

=0.6*5/9.6=0.32397 L

If 1 L= 1000 mL

0.32397 L= ?

(0.32397*1000)

=323.97 mL

Answer: 323.97 mL 9.26 of M nitric acid solution should be used