What is the limiting and excess reactants in the reaction between 3 moles of NH3 and 6 moles of CuO?
3CuO + 2NH3 → 3Cu + N2 + 3H2O
According to the reaction equation for one mole of NH3 we need "\\frac{3}{2}= 1.5" moles of CuO.
Proportion: 1: 1.5
In this problem there are 3 moles of NH3 and 6 moles of CuO
Proportion: 3: 6 = 1 :2
So, NH3 is limiting reactatnt and CuO is excess reactant.
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