To prepare 100 cm3 of NaCl solution with a concentration of 2 mol/dm3 Ar(Na)=23; Ar(Cl)=35.5 are needed?
Moles of NaCl"=2\u00d7\\frac{100}{1000}=0.2moles"
"2Na(s)\n+\nCl\n_2\n(\ng\n)\n \n\u2192\n \n2NaCl(s)"
Hence moles of "Na=0.2" and "Cl=0.1"
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