Answer to Question #237646 in General Chemistry for Esiee

Question

What is the concentration of stock HNO3 which has density 1.50gcm-3 and has purity of 70%

Answer 1

Molar mass MM(HNO₃) = 63 g/mol

Density ρ = 1.42 g/ml

Purity = 70 %

Molarity

$M = \frac{m}{MM \times V} \\ ρ = \frac{m}{V} \\ M = \frac{ρ \times 1000}{MM} \times Purity \\ M = \frac{1.50 \times 1000}{63} \times \frac{70}{100} = 16.66 \;moles/L$

Answer: 16.66 M