when 1000cm3 of a 0.1M of NaOH solution is neutralized by 0.1M H2SO4 what mass of NaSO4 would be formed
2NaOH+h2so4=na2so4+2H2O
1000cm3=1000ml
v(naoh)=1000/22400=0.0045mol
v(na2so4)=0.0022mol
m(na2so4)=142*0.0022=3.17g
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