The decay formula can be written as:
N=N0×2−tt1/2N=N_0\times 2^{-\frac{t}{t_{1/2}}}N=N0×2−t1/2t
Therefore:
t=−log2(NN0)×t1/2=−log2(0.5g100g)×20 minutes≈153 minutest=-log_2(\frac{N}{N_0})\times t_{1/2}=-log_2(\frac{0.5g}{100g})\times 20\,minutes\approx153\,minutest=−log2(N0N)×t1/2=−log2(100g0.5g)×20minutes≈153minutes
Answer: 153 minutes
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