How many grams of magnesium oxide are obtained during the combustion of 2 g of magnesium in fasting according to the reaction 2Mg (s) + O2 (g) -> 2MgO (s). Ar(Mg) = 24.3; Ar(O) = 16.
Moles of magnesium =224.305=0.08moles=\frac{2}{24.305}=0.08moles=24.3052=0.08moles
Ratio= 1:1
Mass of magnesium oxide =40.3044×0.08=3.22grams=40.3044×0.08=3.22grams=40.3044×0.08=3.22grams
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