Calculate the molar solubility of Ag2SO4 when dissolved in water (Ksp = 1.9 x 10-5) (Please give your answer with 2 significant figures.)
s=3^33 √Ksp/4
Ksp43\sqrt[3]{\frac{Ksp}{4}}34Ksp
1.9×10−543\sqrt[3]{\frac{1.9×10^{-5}}{4}}341.9×10−5
= 0.01680987703
= 0.017
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment