The Ksp value for magnesium carbonate, MgCO3, is 5.9 x 10-6. If 2.50 g of magnesium carbonate is placed in 1.00 x 102 mL of water, how much (in g) magnesium carbonate will dissolve? (Please provide your answer with 2 significant figures.)
number of moles of MgCO3 = mass/molar mass = 0.02966 moles
volume = 1.00 × 10² mL = 100 mL = 0.100 L
molarity = 0.02966/0.100 = 0.2966 M
Since, molar mass of magnesium carbonate = 84.32 g/mol.
Grams of magnesium carbonate dissolved in per 1 liter solution (mass concentration)
mass dissolved = 0.2049g/L × 0.100L = 0.02049g
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