Question #236893
The heat of dissolution of potassium carbonate is -30.9 kJ mol-1.
What would be the change in temperature if 4.00 g of potassium carbonate is dissolved in 0.10 L of water?
Expert's answer
∆H = m x s x ∆T
-30.9 = 4.2 × 4 × ∆T
-30.9 = 16.8 × ∆T
∆T = -30.9/16.8
= 1.84°C
