Answer to Question #236893 in General Chemistry for loren

Question

The heat of dissolution of potassium carbonate is -30.9 kJ mol^-1. 

What would be the change in temperature if 4.00 g of potassium carbonate is dissolved in 0.10 L of water?

Answer 1

∆H = m x s x ∆T

-30.9 = 4.2 × 4 × ∆T

-30.9 = 16.8 × ∆T

∆T = -30.9/16.8

= 1.84°C