Consider the reaction of iodine with manganese dioxide
3I2(s) + 2MnO2(s) + 8OH-(aq) ↔ 6I-(aq) + 2MnO4-(aq) + 4H2O(l)
The equilibrium constant for the overall reaction is 8.30 x 10-7. Calculate ΔG° for the reaction at 25° C.
ΔG° =−2.303RTlogK
= 2.303×8.314×298log8.13×10-7
= 5705 × -6.08991
= -34.7kJ
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