Complete and balance the following redox equation. What is the coefficient of H2S when the equation is balanced with the set of smallest whole numbers?
H2S + MnO4- → Mn2+ + SO42– (acidic solution)
MnO4-"\\to"Mn2+
H2 S"\\to"SO42-
MnO4- "\\to" Mn2+ +4H2O
H2S +4H2O"\\to" SO42-
MnO4 +8H+ "\\to" Mn2+ +4H2O
H2S +4H2O"\\to" SO42- +10H+
MnO4- +8H+ +5e"\\to" Mn2+ +4H2O ...(1)
H2S +4H2O"\\to" SO42- +10H+ +8e- ...(2)
8MnO4 +64H+ 4Oe- "\\to" 8Mn2+ +32H2O ...(3)
5H2S + 20H2O "\\to" 5SO42- + 40e- ...(4)
8MnO4 + 64H+ 4Oe- +5H2S +20H2O"\\to" 5SO42- +8Mn2+ +32H2O +5SO42- +5OH+ +40e-
8MnO4- (aq) +14H+ (aq) +5H2S (aq) "\\to" 5SO42- (aq) +8Mn2+ (aq) +12H2O (l) +5SO42- (aq)
The coefficient of H2S is 5
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