Answer to Question #236191 in General Chemistry for Michael

Question

Lead (II) nitrate is reacted with sodium iodide. Calculate the number of Pb²⁺ ions required to form 1.1 g of precipitate. Write the balanced molecular, total ionic, and net ionic equations of the reaction.

 

Atomic Mass:

Pb: 207.2 g/mol

N: 14.0067 g/mol

O: 15.999 g/mol

Na: 22.989769 g/mol

I: 126.90447 g/mol

Note: Use scientific notation with the format (n)e(x) where n = number and x = exponent (Example: 6.022e23 for 6.022 x 10²³)

Answer 1

$=12.262×10 ^{20}ions$