Question #236180

The solubility of the hydroxide of a hypothetical metal, Me, in water is 144.27 g MeOH per 54.88 mL water. Calculate the amount of water in mL needed to dissolve 32.41 g of MeOH.


1
Expert's answer
2021-09-12T23:18:09-0400

144.27 = 54.88

32.41 = ?

= 54.88 × 32.41/144.27

= 12.33ml


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