Since we know that pH+pOH=pKw=14, we proceed to calculate the pH and then the pOH:
[H+]=1.00×10−7MpH=−log[H+]pH=−log(1.00×10−7M)pH=−log(10−7)=−(−7)=7pOH=14−pH=14−7=7
Reference
- Chang, R., & Goldsby, K. A. (2010). Chemistry. Chemistry, 10th ed.; McGraw-Hill Education: New York, NY, USA.
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