Question

A 1.50g sample of a compound, consisting of element chromium and chlorine, was dissolved completely in water. The solution was added to excess silver nitrate solution, AgNO₃ . All the chlorine from the sample was converted to 4.074g of silver chloride precipitate, AgCl. Determine the mass of chlorine and chromium

Answer 1

Cr₂O₃ + 3 C + 3 Cl₂ → 2 CrCl₃ + 3 CO.

Moles of compound $=\frac{1.50}{158.36}=0.0095moles$

Moles of chlorine $=\frac{4.074}{35.453}=0.115moles$