The electrolyte in automobile lead batteries is a 4.04 M sulfuric acid (H 2SO 4) solution. Calculate the mass percent of solute if the density of the solution is 1.161 g/mL. Express final answer in two decimal places.
Solution
"1.161 \\frac{g}{ml}\\times{\\frac{1000ml}{1L}}=1.161 \\times 10^3"
4.04"mol\\times {\\frac{98.1gH_2SO_4}{1mol}}=396.32g"
Mass percent of the solute
"=\\frac{396.32g}{1161g} \\times100=34.14"
Mass percent of H2SO4 = 34.14%
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