Consider a buffer solution made up of H2PO4- and HPO42-. What mole ratio of HPO42- / H2PO4- will give a pH of 6.95? Ka = 6.3 x 10-8
pH = pKa + Log10(base/acid)
-log 6.3 × 10-8 = 7.3
Therefore, log10(base/acid) = pH-pKa
= 6.95 -7.3 = -0.08
= 100.08 = 0.832
or 1/0.832 = 1.2
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