205 gram hydrogen sulfide reacts with 75.0 g oxygen to produce sulfur and water. Find:
a) Gram of sulfur formed
b) gram of excess reactant used up
c) gram of excess reactant that remained unreacted
H2S + O2 --->>H2O + S
Molar mass of H2S = 34.1
= 205/34.1 = 6.0112 moles
Molar mass of oxygen = 31.998
75/31.998 = 2.344 moles
Mole ratio in both cases = 1:1
= 2.344+6.0112 = 8.3552 moles of Sulfur
Molar mass of sulfur = 32.065
= 32.065 × 8.3552 = 267.91g of sulfur
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