calculate the density of a proton given that the mass of a proton in 1.0073 amu and the diameter of a proton is 1.68*10^-15m
Mass of proton = 1.0073amu = 1.0073×1.66054×10−27 kg=1.6726×10−27 kg1.0073\times1.66054\times10^{-27}\ kg=1.6726\times10^{-27 }\ kg1.0073×1.66054×10−27 kg=1.6726×10−27 kg
Volume of proton = 43π(d2)3=43π(1.72×10−152)3\frac{4}{3}\pi({\frac{d}{2}})^3=\frac{4}{3}\pi(\frac{1.72\times 10^{-15}}{2})^334π(2d)3=34π(21.72×10−15)3
=2.66×10−45 m3=2.66\times 10^{-45}\ m^3=2.66×10−45 m3
Density =massvolume=1.6726×10−272.66×10−45=6.288×1017 kg m−3=\frac{mass}{volume}=\frac{1.6726\times 10^{-27}}{2.66\times10^{-45}}=6.288\times 10^{17}\ kg\ m^{-3}=volumemass=2.66×10−451.6726×10−27=6.288×1017 kg m−3
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