Answer to Question #233791 in General Chemistry for Precaution

Question #233791

calculate the density of a proton given that the mass of a proton in 1.0073 amu and the diameter of a proton is 1.68*10^-15m


1
Expert's answer
2021-09-07T02:08:18-0400

Mass of proton = 1.0073amu = 1.0073×1.66054×1027 kg=1.6726×1027 kg1.0073\times1.66054\times10^{-27}\ kg=1.6726\times10^{-27 }\ kg

Volume of proton = 43π(d2)3=43π(1.72×10152)3\frac{4}{3}\pi({\frac{d}{2}})^3=\frac{4}{3}\pi(\frac{1.72\times 10^{-15}}{2})^3

=2.66×1045 m3=2.66\times 10^{-45}\ m^3


Density =massvolume=1.6726×10272.66×1045=6.288×1017 kg m3=\frac{mass}{volume}=\frac{1.6726\times 10^{-27}}{2.66\times10^{-45}}=6.288\times 10^{17}\ kg\ m^{-3}

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