Calculate the mass of chlorine gas contained in a 5.00 dm3 flask at 25°c and 98kPa pressure.
According to ideal gas law:
mM×RT=PV\frac{m}{M}×RT=PVMm×RT=PV
Find the mass:
m=(M×P×V)(R×T)m = \frac{(M×P×V)}{(R×T)}m=(R×T)(M×P×V)
V=0.005m3V = 0.005 m^3V=0.005m3
T=298KT = 298 KT=298K
P=98000PaP = 98000 PaP=98000Pa
R=8.314Jmol−1K−1R = 8.314 Jmol^{-1}K^{-1}R=8.314Jmol−1K−1
M=71g/molM = 71 g/molM=71g/mol
m=(71×98000×0.005)(298×8.314)=14.04gm = \frac{(71×98000×0.005)}{(298×8.314) }= 14.04 gm=(298×8.314)(71×98000×0.005)=14.04g
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