Question #233318

Calculate the mass of chlorine gas contained in a 5.00 dm3 flask at 25°c and 98kPa pressure.


1
Expert's answer
2021-09-06T02:38:48-0400

According to ideal gas law:


mM×RT=PV\frac{m}{M}×RT=PV


Find the mass:

m=(M×P×V)(R×T)m = \frac{(M×P×V)}{(R×T)}


V=0.005m3V = 0.005 m^3

T=298KT = 298 K

P=98000PaP = 98000 Pa

R=8.314Jmol1K1R = 8.314 Jmol^{-1}K^{-1}

M=71g/molM = 71 g/mol


m=(71×98000×0.005)(298×8.314)=14.04gm = \frac{(71×98000×0.005)}{(298×8.314) }= 14.04 g


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