Question

calculate the number of tonnes of CO2 equivalent of 80 kg of N2O

Answer 1

M(N₂O)=44.013 g/mol

n(N₂O) $= \frac{80 \times 10^6 \;g}{44.013 \;g/mol}= 1.8176 \times 10^6 \;mol$

M(CO₂) = 44.01 g/mol

m(CO₂) $= 44.01 \times 1.8176 \times 10^6$

$= 79.99 \times 10^6 \; g = 79.99 \;kg = 0.07999 \;tonnes$

Answer: 0.079 tonnes