calculate the number of tonnes of CO2 equivalent of 80 kg of N2O
M(N2O)=44.013 g/mol
n(N2O) =80×106 g44.013 g/mol=1.8176×106 mol= \frac{80 \times 10^6 \;g}{44.013 \;g/mol}= 1.8176 \times 10^6 \;mol=44.013g/mol80×106g=1.8176×106mol
M(CO2) = 44.01 g/mol
m(CO2) =44.01×1.8176×106= 44.01 \times 1.8176 \times 10^6=44.01×1.8176×106
=79.99×106 g=79.99 kg=0.07999 tonnes= 79.99 \times 10^6 \; g = 79.99 \;kg = 0.07999 \;tonnes=79.99×106g=79.99kg=0.07999tonnes
Answer: 0.079 tonnes
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