"M= 180.948 \\;g\/mol \\\\\n\n\u03c1= 16.4 \\;g\/cm^3"
N=2 for BCC
For BCC
"a= \\frac{4r}{\\sqrt{3}} \\\\\n\n\u03c1 = \\frac{N \\times M}{6.023 \\times 10^{23} \\times a^3} \\\\\n\nr= (\\frac{ 2 \\times 180.948}{16.4 \\times 6.023 \\times 10^{23}})^{1\/3} \\\\\n\n= 3.3212 \\times 10^{-8} \\;cm \\\\\n\n= 3.3212 \\times 10^{-10} \\;m \\\\\n\n= 3.32 \\;\u00c5"
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