Calculate the enthalpy of the following reaction:
2Mg + O2 > 2MgO
Given:
Mg + 2HCl > MgCl2 + H2. H=-21.0 kJ
MgO + 2HCl > MgCl2 + H2O. H=-33.5 kJ
H2 + 1/2 O2 > H2O. H=-76.0 kJ
Enthalpy=(-21)2+(33.5)2-76
-42+67-96
-42-9=-51
=-51kJ
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