X cm³ of 0.15 mol dm³ zinc nitrate solution Zn(NO3)2 is pipetted into a 500 cm³ volumetric flask to produce 500 cm³ of 0.018 mol dm³ zinc nitrate solution. Zn(NO3)2. Determine the value of X.
Molar mass of Zinc nitrate = 189.36
189.36 × 0.018 =3.41×10 = 34.1
= 500× 0.15/34.1
= 2.2cm3
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