Carry out the following operations as if it were a calculation of real experimental results. Express the answer with the correct number of significant figures.
(3.26 × 10−3 mg ) − (7.88 × 10−5 mg )
(326×10−5 mg)−(7.88×10−5 mg)=318.12×10−5 mg=3.18×10−3 mg(326 \times 10^{-5} \;mg) -(7.88 \times 10^{-5} \;mg) \\ = 318.12 \times 10^{-5} \;mg \\ = 3.18 \times 10^{-3} \;mg(326×10−5mg)−(7.88×10−5mg)=318.12×10−5mg=3.18×10−3mg
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