Question #229100

A system delivers 225 J of heat to the surroundings while delivering 645 J of work. Calculate the change in the internal energy, Δ E, of the system

  1. -420 J
  2. 420 J
  3. -870 J
  4. 870 J

Expert's answer

The energy balance from the First Law of Thermodynamics states that the total internal energy ΔUΔU of a system is equal to the energy input minus energy output.

This is the heat QQ minus the work performed WW. Mathematically,


ΔU=QWΔU=Q−W


In this system, heat is lost to the surrounding, which means that QQ is negative. Work being delivered to the surroundings means WW is positive.


Therefore, if Q=225JQ = − 225 J and W=+645JW=+645 J , then the change in internal energy is:


ΔU=225J(+645J)=870JΔU=−225 J−(+645 J)= −870 J

 

The change in internal energy of the system is (3). -870 J.

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