"\u2206T_f=K_fm"
Given : "K_f= 2\u00b0C\/m; T_f=-114.6\u00b0C" (actual freezing point)
m=moles of solute /mass of solvent
"m=170\/(0.25*92)=7.3913molal"
"\u2206T_f=7.3913*2=14.7826\u00b0C"
Thus apparent freezing point is
"T_f'=T_f-14.7826=-128.8426\u00b0C"
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