Solution
KClO4 = 1K+ and 1ClO4: i=2
2"\\times 0.1= 0.2"
Ca(Cl04)= 1Ca2+ and 2ClO4- : i=3
"3\\times 0.1= 0.3"
Al(ClO4)3= 1Al3+ and 3ClO4-: i=4
"4\\times 0.1= 0.4"
Sucrose i= 1
"1\\times0.1= 0.1"
1Na+ and 1Cl- :i=2
"2\\times0.1 =0.2"
Therefore Al(ClO4)3 has the lowest vapour pressure of 0.4
Comments
Leave a comment