Solution
KClO4 = 1K+ and 1ClO4: i=2
2×0.1=0.2\times 0.1= 0.2×0.1=0.2
Ca(Cl04)= 1Ca2+ and 2ClO4- : i=3
3×0.1=0.33\times 0.1= 0.33×0.1=0.3
Al(ClO4)3= 1Al3+ and 3ClO4-: i=4
4×0.1=0.44\times 0.1= 0.44×0.1=0.4
Sucrose i= 1
1×0.1=0.11\times0.1= 0.11×0.1=0.1
1Na+ and 1Cl- :i=2
2×0.1=0.22\times0.1 =0.22×0.1=0.2
Therefore Al(ClO4)3 has the lowest vapour pressure of 0.4
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