Answer to Question #228398 in General Chemistry for vhinz

Question

Find the distance (in nm) between the body-centered atom and one corner atom in Na, given a=0.424 nm.

Answer 1

For B.C.C cell r= $√\frac{3}{4}$

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a so distance between body centered atom and a corner atom is 2r= $√\frac{3}{4}$×a×2

=3.66 A°