Question

Molybdenum forms body-centered cubic crystals and at 20 oC the density is 10.3 g/mL. Calculate the distance between the centers of the nearest molybdenum atoms.

Answer 1

Solution

Density = Z $\times$ $\frac {M}{N}$ $\times{l^3}$

Z is effective number of atoms for Molybdenum (Mo). = 2 .

M is Molar mass of Mo = 95.95 g/ mol.

N = 6.02 × 10²³.

L is edgelength in Cm .

d = 10.3 g / $cm^3.$

M = 95.95 g/ mol.

N = $6.02 × 10^{23}$

Make L subject of the formula

L = 3.16 × 10-8 Cm.