What is the total number of moles present in a 52.0 gram sample of glucose, C6H12O6 (s)? (μc = 12.0 g/mol; μH = 1.0 g/mol; μo = 16.0 g/mol)?
The molar mass of glucose is:
"M(C_6H_{12}O_6)=6\\times{M(C)}+12\\times{M(H)}+6\\times{M(O)=6\\times12.0+12\\times1.0+6\\times16.0=}180g\/mol"
Therefore, the number of moles equals:
"n(C_6H_{12}O_6)=52.0g\\times\\frac{1mol(C_6H_{12}O_6)}{180g}=0.289mol"
Answer: 0.289 mol
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