If 0.250 g of fuel increases the temperature of a calorimeter by 20 °C, and the calorimeter is calibrated at 7.28 kJ/°C, calculate the heat of combustion of fuel per gram. SHOW ALL YOUR WORK
Heat lost by the burning fuel =- heat gained by the calorimeter
"q=-C \\Delta T"
where C is the heat capacity of calorimeter
"q=-7.28 \\times 20 =-145.6 \\;KJ"
Therefore heat of combustion
"=\\frac{-145.6}{0.250} =-582.4 \\;KJ\/g"
The heat required for combustion is -582.4 KJ/g
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