"MgCO_3-->MgO+CO_2"
Moles of "MgO=\\frac{80}{40.3044}=1.94moles"
Mass of "MgCO_3=84.3139\u00d71.94=162.73grams"
Mass"=\\frac{162.73\u00d780}{100}=130.184grams"
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