MgCO3−−>MgO+CO2MgCO_3-->MgO+CO_2MgCO3−−>MgO+CO2
Moles of MgO=8040.3044=1.94molesMgO=\frac{80}{40.3044}=1.94molesMgO=40.304480=1.94moles
Mass of MgCO3=84.3139×1.94=162.73gramsMgCO_3=84.3139×1.94=162.73gramsMgCO3=84.3139×1.94=162.73grams
Mass=162.73×80100=130.184grams=\frac{162.73×80}{100}=130.184grams=100162.73×80=130.184grams
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