1.0 dm3 of an ideal gas at 100 kPa and 25 °C is heated to 50 °C at constant pressure. What is the new volume in dm3?
P1V1T1=P2V2T2\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}T1P1V1=T2P2V2
100000×1273+25=100000×V2273+50\frac{100000 \times 1}{273+25}=\frac{100000\times V_2}{273+50}273+25100000×1=273+50100000×V2
298V2=323298V_2=323298V2=323
V2=323/298=1.084dm3V_2=323/298=1.084dm^3V2=323/298=1.084dm3
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